Subnumerics
Finding NV, therefore numbers w/precalculus
At first I thought this was geometry, but it's precalculus... (the next idea is geometry, which is a good thing because I'm not sure if this way works...
***Can this work? There is a number on one length of each triangle, and a NV on another... Numbers can not be used with NV in an equation. Here is a graph used to create an idea for precalculus... A number must be used to do this to create a triangle with one side given the length of 1.
The precalculus rules must be disassembled completely and reassembled using NV to see if it works.
Here the PH and the Number are located in the same place because it is assumed that the NV and the PH are the same number value to create the number.