Subnumerics

x=x/5

xph<=>xnv=(xph<=>xnv)/5

(5) (xph<=>xnv)=(xph<=>xnv)

(5xph<=>5xnv)=xph<=>xnv

5xph<=>5xnv)-xnv=(xph<=>xnv)-xnv

(5xph<=>5xnv)-xnv=(xph)

-xnv=(xph)/(5xph<=>5xnv)

1=(xph<=>xnv)/(5xph<=>5xnv)

1=1/5

x=1

Here I found out what X is but I got a strange formula... 1 can't equal 1/5... but I was going for trying to find out what x is and I did.

It may be possible that the variable on one side may have been hidden in the subnumerics, which have been eliminated over time. Maybe I need to create a new kind of subnumeric variable to leave on the equation.

Since X is not the same as Xph or Xnv, So how can I leave a variable in Subnumerics?

the answer fow x was supposed to be zero, and not one, so this did not work, or I miscalculated. I will go offline and check.

unless this has a second answer that I do not understand yet 

x=x/5

xph<=>xnv=(xph<=>xnv)/5

(5) (xph<=>xnv)=(xph<=>xnv)

(5xph<=>5xnv)=xph<=>xnv

5xph<=>5xnv)-xnv=(xph<=>xnv)-xnv

(5xph<=>5xnv)-xnv=(xph)

-xnv=(xph)/(5xph<=>5xnv)

1=(xph<=>xnv)/(5xph<=>5xnv)

1=(xph<=>xnv)/(5xph<=>5xnv)

1=(xph)/(5xph<=>4xnv)(xnv)

1=(xph)/(5xph<=>4xnv)

1=(xph<=>xnv)/(5xph<=>4xnv)

1=1/(5xph<=>4xnv)

here I got a different answer, possibly because I worked it differently.

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I wonder if I pit the first answer against the second, which are both equal to 1.

1/5=1/(5xph<=>4xnv)

1/(5xph<=>5xnv)=1/(5xph<=>4xnv)

(5xph<=>4xnv)=(5xph<=>5xnv)

4xnv=5xnv

-1xnv=0

The -1xnv is equal to zero. I am not sure what this means or how this computes.

How is zero, the real answer, related to -1xnv?

In this case, the xph is an unknown. Or maybe it doesn’t exist. I’m not sure what this means. I have encountered something new. 

Somehow the nv effect created zero on the other side of the equation. What does this mean? 

or, if done in reverse,

0nv=xnv Finally! An answer that works

but I made several errors with x

there is a difference between ph, nv, and xph or xnv